7. Binary Search

Arpit Khurana
Oct 20, 2020

Given a sorted (in ascending order) integer array nums of n elements and a target value, write a function to search target in nums. If target exists, then return its index, otherwise return -1.

Example 1:

Input: nums = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4

Example 2:

Input: nums = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1

Note:

  1. You may assume that all elements in nums are unique.
  2. n will be in the range [1, 10000].
  3. The value of each element in nums will be in the range [-9999, 9999].

Solution

class Solution {
public int search(int[] nums, int target) {

int low = 0;
int high = nums.length-1;

while(low<=high) {
int mid = (low+high)/2;

if(nums[mid] == target) {
return mid;
} else if (nums[mid] > target) {
high = mid-1;
} else {
low = mid+1;
}
}

return -1;

}
}

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